Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.MiscellaneousEasy2 minQB
PhysicsEasynumerical

A cricket ball of mass0.15 kgis thrown vertically up by a bowling machine so that it rises to a maximum height of20 mafter leaving the machine. If the part pushing the ball applies a constant forceFon the ball applies a constant forceFon the ball and moves horizontally a distance of0.2 mwhile launching the ball, the value ofF(in N)isg=10 m s-2

Answer:
150.00
Solution:

From work energy theorem F0.2-mg20=0

F=mg200.2

=mg2002

=0.15×10×2002

=150.00 N

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous
⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...