A string of L is fixed at one end and carries a mass M at the other end. The string makes 2 π revolutions per second around the vertical axis through the fixed end as shown in the figure, then the tension in the string is

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PhysicsW.E.P.Vertical circular motionMedium2 minPYQ_2022

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A string of $L$ is fixed at one end and carries a mass $M$ at the other end. The string makes $\frac{π}{2}$ revolutions per second around the vertical axis through the fixed end as shown in the figure, then the tension in the string is

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Solution:

Given: $ω = \frac{2}{π}$ rev.per sec $\Rightarrow ω = 2 π \frac{2}{π} rad / s = 4 rad / s$ The horizontal force balance reads: $T sin θ = MR ω^{2}$ From figure $R = L sin θ$ $\Rightarrow T = M L ω^{2}$ On introducing, $ω = 4 rad / s$ $\Rightarrow T = M L (4)^{2} = 16 ML$

Stream:MHT_CETSubject:PhysicsTopic:W.E.P.Subtopic:Vertical circular motion

⏱ 2mℹ️ Source: PYQ_2022

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