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PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

An object of mass $4 kg$ and another object of mass $1 kg$ are moving such that they have equal kinetic energies. The ratio of the magnitudes of their linear momenta is

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Answer:

Solution:

$K . E_{1}$ of 4kg mass $= \frac{1}{2} (4) v_{1}^{2}$

$K . E_{2}$ of 1kg mass $= \frac{1}{2} (1) v_{2}^{2}$

Since, $K . E_{1} = K . E_{2}$ (given)

We have,

$\frac{1}{2} (4) v_{1}^{2} = \frac{1}{2} (1) v_{2}^{2}$

$\Rightarrow \frac{v_{1}}{v_{2}} = \sqrt{\frac{1}{4}} = \frac{1}{2}$

Now, momentum $| \bar{P} |$ of 4kg mass $= (4) (1) k g \frac{m}{s}$

and, momentum $| {\bar{P}}_{2} |$ of 1kg $= (1) (2) k g \frac{m}{s}$

$∴ \frac{| {\bar{P}}_{1} |}{| {\bar{P}}_{2} |} = \frac{4}{2}$

$= \frac{2}{1}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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