Physics - W.E.P. Question with Solution | TestHub

At a height$\frac{4}{5}\mathrm{h,}$

$\text{Potential energy}=\text{mg}\times \frac{4h}{5}=\frac{4}{5}\text{mgh}$

Total energy = mgh

$\therefore \text{K E at that height}=\text{mgh}-\frac{4}{5}\mathrm{mgh}=\frac{1}{5}\mathrm{mgh}$

$\therefore \text{At a height}\frac{4}{5}h,\text{the ratio of}$

$\frac{\text{KE}}{\text{PE}}=\frac{\frac{1}{5}\text{mgh}}{\frac{4}{5}\text{mgh}}=\frac{1}{4}$