In the system shown in the figure, the block is pulled by applying a force of $40 N$ on the other end of the string. If the kinetic energy of the block increases by $40 J$ in a given interval of time then work done by tension on the block is $(g = 10 m s^{- 2})$

Question

TestHub · Accepted Answer

Work done on block = ∆ K E W = 40 J Net force on the block is = T - M Thus W = F n e t × S 40 = 20 × S ⇒ S = 2 m Work done by tension = T × S cos ⁡ 0 o ⇒ 40 2 1 = 80 J

Physics - W.E.P. Question with Solution | TestHub

Options:

Doubts & Discussion