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PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A chain of length $ℓ < \frac{π R}{2}$ is placed on a smooth surface whose some part is horizontal and some part is on quarter circular of radius $R$ in the vertical plane as shown. Initially the whole part of chain lies in the circular part with one end at topmost point of circular surface. If the mass of chain is $m$ , then work required to pull very slowly the whole chain on horizontal part is –

Options:

Answer:

Solution:

Taking flat surface as reference,

${dU}_{i} = - (\frac{m}{ℓ} Rd θ) \times g \times R [1 - cos θ]$

${dU}_{i} = - \frac{{mgR}^{2}}{ℓ} [1 - cos θ] d θ$

$∴ U_{i} = - \frac{{mgR}^{2}}{ℓ} [(\frac{ℓ}{R}) - sin (\frac{ℓ}{R})]$

and $U_{f} = 0$

$∴ W_{ext} = - Δ U$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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