Physics - W.E.P. Question with Solution | TestHub

In the first case, the centre of gravity is at a height $=\frac{b}{2}$ $\therefore$ Work done $=\mathrm{mgh}=\mathrm{mg}\left(\frac{b}{2}\right)$ In the second case, the height of the centre of gravity $=\frac{L}{2}$ $\therefore$ Work done $=mg\frac{L}{2}\therefore L>b$ $\therefore$ Extra work done $=mg\left(\frac{L-b}{2}\right)$