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PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle of mass $100 g m$ moves in a potential well given by $U = 8 x^{2} - 4 x + 400 j o u l e$ . Find its acceleration at a distance of $25 c m$ from equilibrium in the positive direction

Options:

Answer:

Solution:

We know that $F = - \frac{d U}{d x}$

$F = - \frac{d}{d x} (8 x^{2} - 4 x + 400)$

$F = - (16 x - 4)$

$F = 4 - 16 x$

At equilibrium $4 - 16 x_{0} = 0$ and

$x_{0} = \frac{1}{4} m = 25 cm$

At the given position

$x = (25 + 25) = 50 c m$

$\Rightarrow$ $F = 4 - 16 \times 0 .5 = - 4 N$

or $a = \frac{- 4}{0.1} = - 40 m s^{- 2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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