Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.PowerEasy2 minPYQ_2020

PhysicsEasynumerical

Power supplied to a particle of mass $2 kg$ varies with time as $P = \frac{3 t^{2}}{2} W$ , where $t$ is in seconds. If the velocity of the particle at $t = 0$ is $v = 0$ , then what is the velocity (in $m s^{- 1}$ ) of the particle at $t = 2 s$ ?

Answer:

2.00

Solution:

$\begin{array}{l} K_{f} - K_{i} = \int P \cdot d t \\ \frac{1}{2} m v^{2} - 0 = \int_{0}^{2} (\frac{3}{2} t^{2}) d t \\ \frac{1}{2} (2) v^{2} = \frac{3}{2} {[\frac{t^{3}}{3}]}_{0}^{2} = 4 \\ v = 2 m s^{- 1} \end{array}$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Power

⏱ 2mℹ️ Source: PYQ_2020

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