Two springs of spring constants ' K ′ and ' 2 K ′ are stretched by same force. If ' w 1 ∘ and ' w 2 ' are the energies stored in them respectively then

Energy stored in spring of w 1 = 2 1 k x 2 constant k Th spring of contant 2k w 2 = 2 1 ( 2 k ) x 2 constant k So, w 2 = 2 w 1

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PhysicsW.E.P.MiscellaneousMedium2 minPYQ_2020

PhysicsMediumsingle choice

Two springs of spring constants ' $K^{'}$ and ' $2 K^{'}$ are stretched by same force. If ' $w_{1}^{\circ}$ and ' $w_{2}$ ' are the energies stored in them respectively then

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Solution:

Energy stored in spring of $w_{1} = \frac{1}{2} k x^{2} constant k$ Th spring of contant 2k $w_{2} = \frac{1}{2} (2 k) x^{2} constant k$ So, $w_{2} = 2 w_{1}$

Stream:MHT_CETSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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