A particle moves from a point - 2 i ^ + 5 j ^ to 4 j ^ + 3 k ^ when a force of 4 i ^ + 3 j ^ N is applied. How much work has been done by the force?

S → = r → 2 - r → 1 = 4 j ^ + 3 k ^ - - 2 i ^ + 5 j ^ = 2 i ^ - j ^ + 3 k ^ F → = 4 i ^ + 3 j ^ W = F → . s → = 8 - 3 = 5 J

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PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2020

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A particle moves from a point $(- 2 \hat{i} + 5 \hat{j})$ to $(4 \hat{j} + 3 \hat{k})$ when a force of $(4 \hat{i} + 3 \hat{j}) N$ is applied. How much work has been done by the force?

Options:

Answer:

Solution:

$\vec{S} = {\vec{r}}_{2} - {\vec{r}}_{1} = (4 \hat{j} + 3 \hat{k}) - (- 2 \hat{i} + 5 \hat{j})$

$= 2 \hat{i} - \hat{j} + 3 \hat{k}$

$\vec{F} = 4 \hat{i} + 3 \hat{j}$

$W = \vec{F} . \vec{s} = 8 - 3 = 5 J$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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