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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A force acts on a $30 g$ particle in such a way that the position of the particle as a function of time is given by $x = 3 t - 4 t^{2} + t^{3}$ where $x$ is in meters and $t$ is in seconds. The work done during the first $4$ seconds is

Options:

Answer:

Solution:

$v = \frac{d x}{d t} = 3 - 8 t + 3 t^{2}$

Speed at $t = 0$ is

$v_{0} = 3 m / s$

Speed at $t = 4$ is

$v_{4} = 19 m / s$

According to work energy theorem

$W = \frac{1}{2} m (v_{4}^{2} - v_{0}^{2})$

$W = \frac{1}{2} \times 0.03 \times (1 9^{2} - 3^{2}) = 5.28 J$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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