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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workEasy2 minPYQ_2011

PhysicsEasysingle choice

Force $F$ on a particle moving in a straight line varies with distance $d$ as shown in the figure. The work done on the particle during its displacement of $12 m$ is
NEET 2011 (Screening)

Options:

Answer:

Solution:

Work done $=$ Area under $(F - x)$ graph $= 2 \times (7 - 3) + \frac{1}{2} \times 2 \times (12 - 7) = 8 + \frac{1}{2} \times 10 = 8 + 5 = 13 J$

Stream:NEETSubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: PYQ_2011

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