Physics - W.E.P. Question with Solution | TestHub

$\text{F}\propto {\text{s}}^{-1/3}$

i.e.,  acceleration$\text{a}\propto {\text{s}}^{-1/3}$

or$\text{v}\frac{\text{dv}}{\text{ds}}={\text{Ks}}^{-1/3}\text{ or}$${\text{v}}^2\propto {\text{s}}^{2/3}$

or$\text{v}\propto {\text{s}}^{1/3}$

Now$\text{P}=\text{F}\text{.}\text{v}$

or$\text{P}\propto {\text{s}}^{-1/3}\text{. }{\text{s}}^{1/3}\text{ or }\text{P}\propto {\text{s}}^0$

i.e., power is independent of s.