Physics - W.E.P. Question with Solution | TestHub

Let$p_1=p,p_2=p_1+50\%$of$p_1$

$=p_1+\frac{p_1}{2}=\frac{3p_1}{2}$

$E\propto p^2$

$\Rightarrow \frac{E_2}{E_1}={\left(\frac{p_2}{p_1}\right)}^2={\left(\frac{\frac{3p_1}{2}}{p_1}\right)}^2=\frac{9}{4}$

$\Rightarrow E_2=2.25E_1=E_1+1.25E_1$

$\therefore E_2=E_1+125\%$of$E_1$

i.e., kinetic energy will increase by$125\%$