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PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2013

PhysicsEasysingle choice

A gas expands $0.25 m^{3}$ at constant pressure $1 0^{3} N / m^{2}$ , the work done is

Answer:

Solution:

From the formula of work done $W = p Δ V = 1 0^{3} \times 0.25 = 250 J$

Stream:JIPMERSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2013

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