Physics - W.E.P. Question with Solution | TestHub

Given, mass of the particle $=M$. Charge on the particle $=q$ Electric field $=E$ Initial velocity, $u=0$ $\therefore$ Acceleration, $a=\frac{F}{M}=\frac{qE}{M}$ :.Distance travelled in electric field, $S=ut+\frac{1}{2}a{t}^2$ $$S=\frac{1}{2}\left(\frac{qE}{M}\right)t^2$$ Also, kinetic energy $T=\frac{1}{2}M{\left(\frac{qEt}{M}\right)}^2$ So, $\frac{T}{S}=\frac{\frac{1}{2}M{\left(\frac{qEt}{M}\right)}^2}{\frac{1}{2}\left(\frac{qE}{M}\right)t^2}=qE$ $\Rightarrow$ Ratio of $\frac{T}{S}$ remains constant with time t.