Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Work kinetic energy theoremHard2 minQB

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Passage / Comprehension

In a second ODI match between England and India, Bhuvneshwar Kumar bowled his medium-fast bowling. He starts his run-up from a distance of 50 m from the stumps (bowling end). At the time of bowling a ball, his speed is 36 km/hr, and the speed of the ball is 144 km/hr. If his mass is 70 kg and the mass of the ball is 1/4 kg, and the heat produced in his body is one-tenth of the total work done by him, then:

Energy spent by bowler in throwing one ball is :-

Options:

Answer:

Solution:

work done $= \frac{1}{2} \times 70 \times (36 \times \frac{5}{18})^{2} + \frac{1}{2} \times \frac{1}{4} \times (144 \times \frac{5}{18})^{2} = 3700 J$

Heat produced $= 3700 \times \frac{1}{10} = 370 J$

energy spent $= 3700 + 370 = 4070 J$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

⏱ 2mℹ️ Source: QB

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