A body of mass 6 kg is acted upon by a force which causes a displacement in it given by x = 4 t 2 metre where t is the time in second. The work done by the force in 2 seconds is

Hints : m = 6 kg x = 4 t 2 dt dx = v = 2 t v ( 0 ) = 0 ; v ( 2 ) = 2 2 = 1 K i = 2 1 m ( 0 ) 2 = 0 ; K f = 2 1 m ( 1 ) 2 = 2 1 × 6 × 1 = 3 ; W = K f − K i = 3 − 0 = 3 J

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PhysicsW.E.P.Calculation of workHard2 minPYQ_2011

PhysicsHardsingle choice

A body of mass $6 kg$ is acted upon by a force which causes a displacement in it given by $x = \frac{t ^{2}}{4}$ metre where $t$ is the time in second. The work done by the force in 2 seconds is

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Solution:

$Hints : m = 6 kg x = \frac{t ^{2}}{4} \frac{dx}{dt} = v = \frac{t}{2} v (0) = 0; v (2) = \frac{2}{2} = 1 K_{i} = \frac{1}{2} m (0)^{2} = 0; K_{f} = \frac{1}{2} m (1)^{2} = \frac{1}{2} \times 6 \times 1 = 3; W = K_{f} - K_{i} = 3 - 0 = 3 J$

Stream:WBJEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: PYQ_2011

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