Physics - W.E.P. Question with Solution | TestHub

Here : Weight of block $w=2\mathrm{kN}$, Distance $d=10\mathrm{m}$ Angle of inclination on the plane $\alpha =15^{\circ }$ The block will be pulled up on a smooth plane Hence, force of resistance due to inclination $\begin{array}{rl}F& =w\sin \alpha =2\times 10^3\sin 15^{\circ }\\ & =2\times 10^3\times 0.2588\\ & =0.5176\mathrm{kN}\end{array}$ Now work done, $\begin{array}{rl}W=Fd& =0.5176\times 10^3\times 10\\ & =5.17\mathrm{kJ}\end{array}$