Physics - W.E.P. Question with Solution | TestHub

The potential energy stored in a spring stretched or compressed by a distance $x$ from its equilibrium position is given by the formula:$$U=\frac{1}{2}k{x}^2$$ Given spring constant $k=200\text{N/m}$ and stretch $x=10\text{cm}=0.1\text{m}$.$$U=\frac{1}{2}(200\text{N/m})(0.1\text{m}{)}^2=100\times 0.01\text{J}=1\text{J}$$