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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Work kinetic energy theoremMedium2 minQB

PhysicsMediumsingle choice

The position of a body of mass 2 kg varies with time t as $x = t^{2} + 2 t$ , where x is in meters and t is in seconds. The work done by all the forces acting on the body during the time interval $[2 s, 4 s]$ is :-

Options:

Answer:

Solution:

Differentiate the position to obtain velocity.

$v = \frac{d x}{d t} = 2 t + 2$

$v (2) = 6 m/s$

$v (4) = 10 m/s$

Net work equals the change in kinetic energy.

$W_{net} = Δ K$

$W_{net} = \frac{1}{2} (2) (1 0^{2} - 6^{2})$

$W_{net} = 64 J$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

⏱ 2mℹ️ Source: QB

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