In young's double slit experiment relative intensity at a point on the screen may be defined as ratio of intensity at that point to the maximum intensity on the screen. Light of wavelength 7500 Å

Question

In young's double slit experiment relative intensity at a point on the screen may be defined as ratio of intensity at that point to the maximum intensity on the screen. Light of wavelength 7500 Å passing through a double slit, produces interference pattern of relative intensity variation as shown in Fig. $θ$ on horizontal axis represents the angular position of a point on the screen. Choose the INCORRECT statements.

TestHub · Accepted Answer

I m i n ​ I m a x ​ ​ = 1 9 ​ I m a x ​ I m i n ​ ​ = ( a 1 ​ + a 2 ​ a 1 ​ − a 2 ​ ​ ) 2 = 9 1 ​ I m i n ​ I m a x ​ ​ = ( a 1 ​ − a 2 ​ a 1 ​ + a 2 ​ ​ ) 2 = 1 9 ​ ⇒ a 1 ​ + a 2 ​ a 1 ​ − a 2 ​ ​ = 3 1 ​ ⇒ a 1 ​ − a 2 ​ a 1 ​ + a 2 ​ ​ = 1 3 ​ ⇒ a 1 ​ : a 2 ​ = 2 : 1 (Options B, D false) Δ θ ≈ 1 ∘ Interference condition: d sin θ = mλ ⇒ d Δ θ = λ d = Δ θ λ ​ = ( 1 ∘ × π /180 ) 7500 × 1 0 − 10 ​ ≈ 4 × 1 0 − 5 m d = 0.04 mm (A) is also false

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JEE Advanced 2026