For obtaining maximum contrast between the bright and dark fringes in an interference pattern, the intensities of the two light coherent sources should be

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The contrast of an interference pattern is determined by the visibility, which is given by $V = \frac{I _{ma x} - I _{min}}{I _{ma x} + I _{min}}$ .

For maximum contrast, the minimum intensity $I_{min}$ should be zero.

The minimum intensity in an interference pattern is given by $I_{min} = (I_{1} - I_{2})^{2}$ .

For $I_{min} = 0$ , we must have $I_{1} = I_{2}$ , which implies $I_{1} = I_{2}$ .

Thus, the intensities of the two coherent sources should be equal.

Answer: equal

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