In Young's double slit experiment the intensity at a point on the screen is K , where path difference is λ . What will be the intensity at the point where path difference is 4 λ ?

Question

In Young's double slit experiment the intensity at a point on the screen is K , where path difference is λ . What will be the intensity at the point where path difference is 4 λ ​ ?

TestHub · Accepted Answer

I = 2 I 0 ​ ( 1 + cos ϕ ) ϕ = λ 2 π x ​ , where x is the path as difference. ∴ K = 2 I 0 ​ ( 1 + cos ( λ 2 π ​ × λ ) ) = 4 I 0 ​ Now, for path difference 4 λ ​ ​ K ′ = 2 I 0 ​ ( 1 + cos ( λ 2 π ​ × 4 λ ​ ) ) = 2 I 0 ​ ∴ K ′ = 2 K ​ ​

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