The width of one of the two slits in Young's double slit experiment is d while that of the other slit is x d . If the ratio of the maximum to the minimum intensity in the interference pattern on

Question

The width of one of the two slits in Young's double slit experiment is d while that of the other slit is x d . If the ratio of the maximum to the minimum intensity in the interference pattern on the screen is 9 : 4 then what is the value of x ? (Assume that the field strength varies according to the slit width.)

TestHub · Accepted Answer

​ I ∝ ( width ) 2 ( I 1 ​ ​ − I 2 ​ ​ I 1 ​ ​ + I 2 ​ ​ ​ ) 2 = 4 9 ​ I 1 ​ ​ − I 2 ​ ​ I 1 ​ ​ + I 2 ​ ​ ​ = 2 3 ​ ( x − 1 ) d ( x + 1 ) d ​ = 2 3 ​ ⇒ 3 x − 3 = 2 x + 2 x = 5 ​

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