In a Fraunhofer diffraction at single slit of width d with incident light of wavelength 5500 A ˚ , the first minimum is observed, at angle 3 0 ∘ . The first secondary maximum is observed at an angle θ

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In a Fraunhofer diffraction at single slit of width d with incident light of wavelength 5500 A ˚ , the first minimum is observed, at angle 3 0 ∘ . The first secondary maximum is observed at an angle θ =

TestHub · Accepted Answer

Slit width = d λ = 5500 A ˚ = 5.5 × 1 0 − 7 m , θ n ​ = 3 0 ∘ For first secondary minima, d sin θ n ​ = λ d = s i n θ n ​ λ ​ = s i n 3 0 ∘ 5.5 × 1 0 − 7 ​ = 11 × 1 0 − 7 m For first secondary maxima, d sin θ n ​ = 2 3 λ ​ i. e. sin θ n ​ = 2 d 3 λ ​ = 2 × 11 × 1 0 − 7 3 × 5.5 × 1 0 − 7 ​ sin θ n ​ = 4 3 ​ or θ n ​ = sin − 1 ( 3/4 )

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