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PhysicsWave OpticsYDSEEasy2 minPYQ_2022
PhysicsEasynumerical

In a Young's double slit experiment, a laser light of560 nmproduces an interference pattern with consecutive bright fringes' separation of7.2 mm. Now another light is used to produce an interference pattern with consecutive bright fringes' separation of8.1 mm. The wavelength of second light is _____nm.

Answer:
630.00
Solution:

Given here: λ1=560×10-9 mβ1=7.2×10-3 m and β2=8.1×10-3 m.

Let d be the width and D be the distance between slit and screen then fringe width, β=λDd.

Thus, from above,  βλ

So, the wavelength of second light is λ2=β2β1λ1=98λ1

   λ2=98×560=630 nm.

Stream:JEESubject:PhysicsTopic:Wave OpticsSubtopic:YDSE
2mℹ️ Source: PYQ_2022

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