After passing through a polariser a linearly polarised light of intensity I is incident on an analyser making an angle of 3 0 ∘ with that of the polariser. The intensity of light emitted from the analyser will be :NEET 2022 (Phase 2)

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PhysicsWave OpticsPolarizationEasy2 minPYQ_2022

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After passing through a polariser a linearly polarised light of intensity $I$ is incident on an analyser making an angle of $3 0^{\circ}$ with that of the polariser. The intensity of light emitted from the analyser will be :NEET 2022 (Phase 2)

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Solution:

As per Malus law, $I = I_{0} cos^{2} ϕ$ , where symbols have their usual meanings. $I^{'} = I cos^{2} 3 0^{\circ} I^{'} = I (\frac{3}{2})^{2} I^{'} = \frac{3 I}{4}$

Stream:NEETSubject:PhysicsTopic:Wave OpticsSubtopic:Polarization

⏱ 2mℹ️ Source: PYQ_2022

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