In a Young's double slit experiment, light of 500 nm is used to produce and interference pattern. When the distance between the slits is 0 . 05 mm , the angular width (in degree) of the fringes f

Question

In a Young's double slit experiment, light of $500 nm$ is used to produce and interference pattern. When the distance between the slits is $0.05 mm,$ the angular width (in degree) of the fringes formed on the distance screen is close to :

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Answer:

B

Solution:

$β_{0} = \frac{λ}{d} = \frac{500 \times 10^{- 9}}{5 \times 10^{- 5}} = 10^{- 2}$ rad
$∴ β_{0} = 0 .57 °$

TestHub · Accepted Answer

β 0 = λ d = 500 × 10 − 9 5 × 10 − 5 = 10 − 2 rad ∴ β 0 = 0 .57 °

Physics - Wave Optics Question with Solution | TestHub

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