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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEMedium2 minPYQ_2022

PhysicsMediumsingle choice

In biprism experiment, the wavelength $λ$ is used to obtain an interference pattern. Then fringe width is $W_{1}$ at distance $D_{1}$ from the screen when the screen is moved towards biprism, fringe width becomes $W_{2}$ at distance $D_{2}$ The distance between two virtual images of the slit is

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Solution:

Fringe width $= \frac{λ D}{d}$ $W_{1} = \frac{λ D _{1}}{d}$ $w_{2} = \frac{λ D _{2}}{d}$ $Δ w = w_{1} - w_{2} = \frac{λ}{d} (D_{1} - D_{2}) \Rightarrow d = \frac{λ ( D _{1} - D _{2} )}{( w _{1} - w _{2} )}$

Stream:MHT_CETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2022

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