In a single-slit diffraction pattern, the position of first secondary maximum is at 3 0 ∘ , then what will be the angular position of second minima?

For first secondary maxima, sin θ 1 = 1 + 1 2 λ a = 3 λ 2 a ⇒ sin 3 0 o = 3 λ 2 a ⇒ λ a = 1 3 For second minima, sin ⁡ θ = 2 λ a = 2 3 or θ = sin - 1 2 / 3

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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsDiffractionEasy2 minPYQ_2020

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In a single-slit diffraction pattern, the position of first secondary maximum is at $3 0^{\circ}$ , then what will be the angular position of second minima?

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Answer:

Solution:

For first secondary maxima,
$\sin θ_{1} = (1 + \frac{1}{2}) \frac{λ}{a} = \frac{3 λ}{2 a}$ $\Rightarrow \sin 3 0^{o} = \frac{3 λ}{2 a}$

$\Rightarrow \frac{λ}{a} = \frac{1}{3}$

For second minima,
$\sin θ = \frac{2 λ}{a} = \frac{2}{3}$ or $θ = \sin^{- 1} (2 / 3)$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:Diffraction

⏱ 2mℹ️ Source: PYQ_2020

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