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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEMedium2 minPYQ_2021

PhysicsMediumsingle choice

In YDSE, the distance of the slits from the screen is increased by $25%$ and the separation between the slits is halved. If ' $W$ ' represents the original fringe width, the new fringe width is

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Solution:

$E = \frac{λ D}{d} ∴ \frac{W _{2}}{W _{1}} = \frac{D _{2}}{D _{1}} \cdot \frac{d _{1}}{d _{2}} D_{2} = 1.25 D_{1} and d_{2} = \frac{d _{1}}{2} ∴ \frac{W _{2}}{W _{1}} = 1.25 \times 2 = 2.5 ∴ W_{2} = 2.5 W$

Stream:MHT_CETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2021

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