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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEHard2 minPYQ_2021

PhysicsHardsingle choice

A double slit experiment is immersed in water of refractive index 1.33. The slit separations $1 mm$ and the distance between slit and screen is $1.33 m$ . The slits are illuminated by a light of wavelength $6300 \overset{˚}{A}$ . The fringe width is

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Solution:

$d = 1 mm = 1 0^{- 3} m, D = 1.33 m λ = 6300 \overset{˚}{A} = 6.3 \times 1 0^{- 7} m$ $λ_{w} =$ wavelength in water $= \frac{6.3 \times 1 0 ^{- 7}}{1.33} m$ Fringe width, $X = \frac{λ _{w} D}{d} = \frac{6.3 \times 1 0 ^{- 7} \times 1.33}{1.33 \times 1 0 ^{- 3}} = 6.3 \times 1 0^{- 4} m$

Stream:MHT_CETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2021

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