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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsDiffractionEasy2 minPYQ_2020

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Light of wavelength $λ = 5000 Å$ falls normally on a narrow slit. A screen placed at a distance of $1 m$ from the slit and perpendicular to the direction of light. First minima of the diffraction pattern is situated at $5 m m$ from the centre of central maximum. The width of the slit is

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Answer:

Solution:

Position of $n^{t h}$ minima

$x_{n} = \frac{n λ D}{d}$

$5 \times 1 0^{- 3} = \frac{1 \times 5000 \times 1 0^{- 10} \times 1}{d}$

$d = 1 0^{- 4} m = 0.1 m m$ .

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:Diffraction

⏱ 2mℹ️ Source: PYQ_2020

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