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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minPYQ_2020

PhysicsEasysingle choice

In young's double-slit experiment, the intensity of light at a point on the screen where the path difference is $λ$ is $I, λ$ being the wavelength of light used. The intensity at a point where the path difference is $\frac{λ}{4}$ will be

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Solution:

For path difference $λ$ , phase difference $= 2 π (ϕ = \frac{2 π}{λ} x = \frac{2 π}{λ} . λ = 2 π)$

$\Rightarrow I = I_{0} + I_{0} + 2 I_{0} \cos 2 π$

$\Rightarrow I = 4 I_{0} (∴ \cos 2 π = 1)$

For $x = \frac{λ}{4}$ , phase difference $= \frac{π}{2}$

$∴ I^{'} = I_{1} + I_{2} + 2 \sqrt{I_{1}} \sqrt{I_{2}} \cos \frac{π}{2}$

If $I_{1} = I_{2} = I_{0} then I^{'} = 2 I_{0} = 2. \frac{I}{4} = \frac{I}{2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2020

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