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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minPYQ_2020

PhysicsEasysingle choice

In Young’s double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes:NEET 2020 (Phase 1)

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Answer:

Solution:

$β = \frac{λ D}{d}$

$β^{'} = \frac{λ D^{'}}{d^{'}}$

$D^{'} = 2 D, d^{'} = \frac{d}{2}$

$β^{'} = \frac{λ \times 2 D}{\frac{d}{2}} = \frac{4 λ D}{d}$

$β^{'} = 4 β$

Fringe width becomes $4$ times.

Stream:NEETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2020

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