Physics - Wave Optics Question with Solution | TestHub

$\text{Path difference} =\frac{\text{xd}}{\text{D}} \Rightarrow \text{Path difference} =\frac{4\times 10^{-5}\times \text{0.25}\times 10^{-2}}{1}$

$\text{Path difference} =1\times 10^{-7}$

$\text{Phase difference} =\frac{\text{path diff.}}{\lambda }\times 2\pi \Rightarrow \text{Phase difference} =\frac{1\times 10^{-7}}{6\times 10^{-7}}\times 2\pi$

$\text{Phase difference} =\frac{2\pi }{6} \Rightarrow \text{Phase difference} =\frac{\pi }{3} \Rightarrow \varphi =60^{\circ }$

${\text{I}}_{\text{R}}={\text{I}}_1+{\text{I}}_2+2\sqrt{{\text{I}}_1{\text{I}}_2}cos60^{\circ } \Rightarrow {\text{I}}_{\text{R}}={\text{I}}_{}+{\text{I}}_{}+2\text{I}\times \frac{1}{2}$

${\text{I}}_{\text{R}}=3\text{I} \Rightarrow {\text{I}}_{\text{R}}=\frac{3{\text{I}}_0}{4}$