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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsDiffractionEasy2 minPYQ_2020

PhysicsEasysingle choice

The first diffraction minimum due to single slit diffraction is at an angle $θ$ for a light of wavelength $5000 Å$ . If the width of the slit is $1 \times 10^{- 4} cm$ , then the value of $θ$ is

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Answer:

Solution:

The distance of first diffraction minimum from the central principal maximum.

$x = \frac{D λ}{d}$

Since $\frac{x}{D} = \frac{λ}{d}$

Or $d = \frac{λ}{\sin θ}$

$\sin θ = \frac{λ}{d} = \frac{5000 \times 10^{- 10}}{1 \times 10^{- 6}} = 0.5 = \sin 30^{o}$

$θ = 30^{o}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:Diffraction

⏱ 2mℹ️ Source: PYQ_2020

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