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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsDiffractionEasy2 minPYQ_2020

PhysicsEasysingle choice

Consider Fraunhofer diffraction pattern obtained with a single slit illuminated at normal incidence. At the angular position of the first diffraction minimum, the phase difference (in radians) between the wavelets from the opposite edges of the slit is

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Answer:

Solution:

For Ist minimum $θ = \frac{λ}{a}$ .

and $ϕ = \frac{2 π}{λ} . Δ x = \frac{2 π}{λ} a \sin θ$

$ϕ = \frac{2 π}{λ} . a θ = \frac{2 π}{λ} a \frac{λ}{a}$

$∴ ϕ = 2 π$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:Diffraction

⏱ 2mℹ️ Source: PYQ_2020

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