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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsDiffractionEasy2 minPYQ_2020

PhysicsEasysingle choice

A light of wavelength $6328 Å$ is incident normally on a slit of width $0.2 mm$ . The angular width of the central maximum on the screen will be

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Answer:

Solution:

$a \sin θ = n λ$

$\sin θ = \frac{n λ}{a} = \frac{6328 \times 10^{- 10} \times 1}{0 .2 \times 10^{- 3}}$

$= 3164 \times 10^{- 6} r a d = 0.003164 r a d$

$∴$ Angular width $= 2 θ$

$= 2 \times 0.003164 \times \frac{180 °}{π} = 0.36 °$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:Diffraction

⏱ 2mℹ️ Source: PYQ_2020

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