Physics - Wave Optics Question with Solution | TestHub

$\because$in the double-slit experiment

${\mathrm{I}}_{\mathrm{net}}={\mathrm{I}}_1+{\mathrm{I}}_2+2\sqrt{{\mathrm{I}}_1{\mathrm{I}}_2}\cos \mathrm{\varphi }$

When${\mathrm{I}}_1={\mathrm{I}}_2$and$\cos \mathrm{\varphi }=+1$

we get${\mathrm{I}}_{\max }=4{\mathrm{I}}_1$

$\therefore$maximum intensity in the double-slit interference

$=4$(maximum intensity of single slit experiment)