Physics - Wave Optics Question with Solution | TestHub

If the polarising sheet is making an angle $\theta$ with the first polarid, then energy of transmitted light, according to law of Malus, will become

$\mathrm{I}=\frac{{\mathrm{I}}_0}{2}\times {\cos }^2\mathrm{\theta }\times {\cos }^2(90-\mathrm{\theta })$

  $=\frac{{\mathrm{I}}_0}{2}\times {\cos }^2\mathrm{\theta }\times {\sin }^2\mathrm{\theta }$

The intensity of light transmitted from the analyser will be maximum when  $\mathrm{\theta }=45°$.