In Young's experiment, the wavelength of red light is 7.8 × 10 - 8 c m and that of blue light is 5.2 × 10 - 8 c m . Value of n for which ( n + 1 ) th blue bright fringe coincides with n th red fringe is

As we know that n 1 λ 1 = n 2 λ 2 ∴ n 2 n 1 = λ 1 λ 2 = 7.8 × 10 - 8 5.2 × 10 - 8 = 3 2 Also n 2 - n 1 = 1 ∴ n 1 = 2

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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minPYQ_2020

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In Young's experiment, the wavelength of red light is $7.8 \times 10^{- 8} c m$ and that of blue light is $5.2 \times 10^{- 8} c m$ . Value of n for which $(n + 1)^{th}$ blue bright fringe coincides with $n^{th}$ red fringe is

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Answer:

Solution:

As we know that $n_{1} λ_{1} = n_{2} λ_{2}$

$∴ \frac{n_{2}}{n_{1}} = \frac{λ_{1}}{λ_{2}} = \frac{7.8 \times 10^{- 8}}{5.2 \times 10^{- 8}} = \frac{3}{2}$

Also $n_{2} - n_{1} = 1$

$∴ n_{1} = 2$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2020

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