In YDSE , intensity at central maxima is I 0 . The ratio I I 0 , at path difference λ 8 on the screen from central maxima, is closed to

∆ ϕ = 2 π λ × λ 8 = π 4 I = I 0 cos 2 ⁡ π 8 = I 0 1 + cos ⁡ π / 4 2 = I 0 1 + 1 2 2 = 0.85 I 0

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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minPYQ_2020

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In $YDSE$ , intensity at central maxima is $I_{0}$ . The ratio $\frac{I}{I_{0}}$ , at path difference $\frac{λ}{8}$ on the screen from central maxima, is closed to

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Answer:

Solution:

$∆ ϕ = \frac{2 π}{λ} \times \frac{λ}{8} = \frac{π}{4}$

$I = I_{0} \cos^{2} \frac{π}{8}$

$= I_{0} (\frac{1 + \cos π / 4}{2})$

$= I_{0} (\frac{1 + \frac{1}{\sqrt{2}}}{2}) = 0.85 I_{0}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2020

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