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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minPYQ_2020

PhysicsEasysingle choice

In Young's experiment, the third bright band for the wavelength of light source $A$ having wavelength $6000 Å$ coincides with the fourth bright band for source $B$ in the same arrangement. Wavelength of light emitted by source $B$ is

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Answer:

Solution:

As given, $\frac{D}{d} \times 3 \times 6 \times 10^{- 7}$
$= \frac{D}{d} \times 4 \times λ_{2}$

$\Rightarrow λ_{2} = \frac{3 \times 6 \times 10^{- 7}}{4}$

$= 4.5 \times 10^{- 7} m$
$= 4500 Å$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2020

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