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Physics - Wave Optics Question with Solution | TestHub

PhysicsWave OpticsYDSEEasy2 minPYQ_2020

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A two-slit Young's interference experiment is done with monochromatic light of wavelength $6000 \overset{\circ}{A}$ . These slits are $2 mm$ apart. The fringes are observed on a screen placed $10 cm$ away from the slits. A transparent plate of thickness of $0.5 mm$ is placed in front of one of the slits. It is found that the interference pattern shifts by $5 mm$ . What is the refractive index of the transparent plate?

Options:

Answer:

Solution:

$Shift = (μ - 1) \frac{tD}{d}$

$5 \times 1 0^{- 3} = (μ - 1) \times \frac{(0.5) \times 1 0^{- 3} \times 10 \times 1 0^{- 2}}{2 \times 1 0^{- 3}}$

$\Rightarrow (μ - 1) = \frac{1}{5}$

$\Rightarrow μ = \frac{6}{5} = 1.2$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:YDSE

⏱ 2mℹ️ Source: PYQ_2020

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