Physics - Wave Optics Question with Solution | TestHub

In Young's double slit experiment, the resultant intensity of light at a point on the screen is 'I' when the path difference is ${\lambda }^{\prime }$ '. When the path difference is $\frac{\lambda }{4}$, the intensity at a point will be $(\lambda =$ wavelength of light, $\cos 180^{\circ }=-1,\cos 45^{\circ }=\frac{1}{\sqrt{2}}$ )