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PhysicsWave OpticsDiffractionEasy2 minPYQ_2020

PhysicsEasysingle choice

Light of wavelength $5000 Å$ is incident over a slit of width $1 μm$ . The angular width of central maxima will be

Answer:

Solution:

For first minima
$\sin θ = \frac{λ}{a} = \frac{5000 \times 10^{- 10}}{1 \times 10^{- 6}} = \frac{1}{2}$
$\Rightarrow$ $θ = 30 °$

So the angular width of the central maxima is

$2 θ = 60 °$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Wave OpticsSubtopic:Diffraction

⏱ 2mℹ️ Source: PYQ_2020

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