Physics - Wave Optics Question with Solution | TestHub

In diffraction of light at a single slit, the pattern obtained consists of a central bright band having alternate dark and bright bands of decreasing intensity on both sides.

For n^th minima (secondary),

$\sin {\mathrm{\theta }}_{\mathrm{n}}=\frac{\mathrm{n\lambda }}{\mathrm{a}}\mathrm{ }$

For n^thmaxima (secondary),

$\sin {\mathrm{\theta }}_{\mathrm{n}}=\left(2\mathrm{n}+1\right)\frac{\mathrm{\lambda }}{2\mathrm{a}}$

Thus, point$5$corresponds to the path difference of extreme rays equal to$2\mathrm{\lambda }$.